The line \[y=mx+c\]is a normal to the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}}=1\], if \[c=\]

\[\frac{({{a}^{2}}-{{b}^{2}})m}{\sqrt{{{a}^{2}}+{{b}^{2}}}}\]

\[\frac{({{a}^{2}}+{{b}^{2}})m}{\sqrt{{{a}^{2}}+{{b}^{2}}{{m}^{2}}}}\]

\[-\frac{({{a}^{2}}-{{b}^{2}})m}{\sqrt{{{a}^{2}}+{{b}^{2}}{{m}^{2}}}}\]

The line \[y=mx+c\]is a normal to the ellipse \[\frac{{{x}^{2}}}{{{a}^

1.	The line \[y=mx+c\]is a normal to the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}}=1\], if \[c=\]
A.	\[-(2am+b{{m}^{2}})\]
B.	\[\frac{({{a}^{2}}+{{b}^{2}})m}{\sqrt{{{a}^{2}}+{{b}^{2}}{{m}^{2}}}}\]
C.	\[-\frac{({{a}^{2}}-{{b}^{2}})m}{\sqrt{{{a}^{2}}+{{b}^{2}}{{m}^{2}}}}\]
D.	\[\frac{({{a}^{2}}-{{b}^{2}})m}{\sqrt{{{a}^{2}}+{{b}^{2}}}}\]
Answer» D. \[\frac{({{a}^{2}}-{{b}^{2}})m}{\sqrt{{{a}^{2}}+{{b}^{2}}}}\]

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The line \[y=mx+c\]is a normal to the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}}=1\], if \[c=\]

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