The line \[\frac{x+3}{3}=\frac{y-2}{-2}=\frac{z+1}{1}\] and the plane \[4x+5y+3z-5=0\] intersect at a point

The line \[\frac{x+3}{3}=\frac{y-2}{-2}=\frac{z+1}{1}\] and the plane

1.	The line \[\frac{x+3}{3}=\frac{y-2}{-2}=\frac{z+1}{1}\] and the plane \[4x+5y+3z-5=0\] intersect at a point
A.	(3, 1, ?2)
B.	(3, ? 2, 1)
C.	(2, ?1, 3)
D.	(?1, ?2, ?3)
Answer» C. (2, ?1, 3)

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The line \[\frac{x+3}{3}=\frac{y-2}{-2}=\frac{z+1}{1}\] and the plane \[4x+5y+3z-5=0\] intersect at a point

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