The line\[\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}\]is parallel to the plane [BIT Ranchi 1991; Pb. CET 1991]

The line\[\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}\]is parallel to

1.	The line\[\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}\]is parallel to the plane [BIT Ranchi 1991; Pb. CET 1991]
A.	\[3x+4y+5z=7\]
B.	\[2x+y-2z=0\]
C.	\[x+y-z=2\]
D.	\[2x+3y+4z=0\]
Answer» C. \[x+y-z=2\]

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The line\[\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}\]is parallel to the plane [BIT Ranchi 1991; Pb. CET 1991]

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