The limit \[\underset{x\to 0}{\mathop{\lim }}\,{{(cosx)}^{1/\sin x\frac{1}{\sin x}}}\] is equal to

The limit \[\underset{x\to 0}{\mathop{\lim }}\,{{(cosx)}^{1/\sin x\fra

1.	The limit \[\underset{x\to 0}{\mathop{\lim }}\,{{(cosx)}^{1/\sin x\frac{1}{\sin x}}}\] is equal to
A.	\[e\]
B.	\[{{e}^{-1}}\]
C.	1
D.	Does not exist
Answer» D. Does not exist

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The limit \[\underset{x\to 0}{\mathop{\lim }}\,{{(cosx)}^{1/\sin x\frac{1}{\sin x}}}\] is equal to

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