MCQOPTIONS
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| 1. |
The length of the shadow of a pole inclined at \[10{}^\circ \] to the vertical towards the sun is 2.05 meters, when the elevation of the sun is \[38{}^\circ .\] The length of the pole is |
| A. | \[\frac{2.05\sin 38{}^\circ }{\sin 42{}^\circ }\] |
| B. | \[\frac{2.05\sin 42{}^\circ }{\sin 38{}^\circ }\] |
| C. | \[\frac{2.05\cos 38{}^\circ }{\cos 42{}^\circ }\] |
| D. | None of these |
| Answer» B. \[\frac{2.05\sin 42{}^\circ }{\sin 38{}^\circ }\] | |