1.

The length of an astronomical telescope for normal vision (relaxed eye) (fo = focal length of objective lens and fe  = focal length of eye lens) is [EAMCET (Med.) 1995; CPMT 1999; BVP 2003]

A.            \[{{f}_{o}}\times {{f}_{e}}\]  
B.            \[\frac{{{f}_{o}}}{{{f}_{e}}}\]
C.            \[{{f}_{o}}+{{f}_{e}}\]      
D.            \[{{f}_{o}}-{{f}_{e}}\]
Answer» D.            \[{{f}_{o}}-{{f}_{e}}\]


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