The length of a wire of a potentiometer is 100 cm, and the emf of its standard cell is E volt. It is employed to measure the e.m.f of a battery whose internal resistance is 0.5 W. If the balance point is obtained at l = 30 cm from the positive end, the e.m.f. of the battery is [AIEEE 2003]

Question

The length of a wire of a potentiometer is 100 cm, and the emf of its standard cell is E volt.  It is employed to measure the e.m.f of a battery whose internal resistance is 0.5 W.  If the balance point is obtained at l = 30 cm from the positive end, the e.m.f. of the battery is                              [AIEEE 2003]

TuteeHUB · Accepted Answer

$$\frac{30E}{100.5}$$

TuteeHUB · Answer

$$\frac{30E}{100}$$

TuteeHUB · Answer

$$\frac{30E}{(100-0.5)}$$

TuteeHUB · Answer

$$\frac{30(E-0.5i)}{100}$$, where i is the current in the potentiometer

1.	The length of a wire of a potentiometer is 100 cm, and the emf of its standard cell is E volt. It is employed to measure the e.m.f of a battery whose internal resistance is 0.5 W. If the balance point is obtained at l = 30 cm from the positive end, the e.m.f. of the battery is [AIEEE 2003]
A.	\[\frac{30E}{100}\]
B.	\[\frac{30E}{100.5}\]
C.	\[\frac{30E}{(100-0.5)}\]
D.	\[\frac{30(E-0.5i)}{100}\], where i is the current in the potentiometer
Answer» B. \[\frac{30E}{100.5}\]

The length of a wire of a potentiometer is 100 cm, and the emf of its standard cell is E volt. It is employed to measure the e.m.f of a battery whose internal resistance is 0.5 W. If the balance point is obtained at l = 30 cm from the positive end, the e.m.f. of the battery is [AIEEE 2003]

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