1.

The least positive solution of \[\cot \left( \frac{\pi }{3\sqrt{3}}\sin 2x \right)=\sqrt{3}\]lies in

A. \[\left( 0,\frac{\pi }{6} \right]\]     
B. \[\left( \frac{\pi }{9},\frac{\pi }{6} \right)\]
C. \[\left( \frac{\pi }{12},\frac{\pi }{9} \right]\]         
D. \[\left( \frac{\pi }{3},\frac{\pi }{2} \right]\]
Answer» B. \[\left( \frac{\pi }{9},\frac{\pi }{6} \right)\]


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