The inverse matrix of \[\left[ \begin{matrix} 0 & 1 & 2 \\ 1 & 2 & 3 \\ 3 & 1 & 1 \\ \end{matrix} \right],\]is [MP PET 2003]

\[\left[ \begin{matrix} \frac{1}{2} & -4 & \frac{5}{2} \\ 1 & -6 & 3 \\ 1 & 2 & -1 \\ \end{matrix} \right]\]

\[\left[ \begin{matrix} \frac{1}{2} & -\frac{1}{2} & \frac{1}{2} \\ -4 & 3 & -1 \\ \frac{5}{2} & \frac{-3}{2} & \frac{1}{2} \\ \end{matrix} \right]\]

\[\frac{1}{2}\left[ \begin{matrix} 1 & 2 & 3 \\ 3 & 2 & 1 \\ 4 & 2 & 3 \\ \end{matrix} \right]\]

\[\frac{1}{2}\left[ \begin{matrix} 1 & -1 & -1 \\ -8 & 6 & -2 \\ 5 & -3 & 1 \\ \end{matrix} \right]\]

The inverse matrix of \[\left[ \begin{matrix} 0 & 1 & 2 \\

1.	The inverse matrix of \[\left[ \begin{matrix} 0 & 1 & 2 \\ 1 & 2 & 3 \\ 3 & 1 & 1 \\ \end{matrix} \right],\]is [MP PET 2003]
A.	\[\left[ \begin{matrix} \frac{1}{2} & -\frac{1}{2} & \frac{1}{2} \\ -4 & 3 & -1 \\ \frac{5}{2} & \frac{-3}{2} & \frac{1}{2} \\ \end{matrix} \right]\]
B.	\[\left[ \begin{matrix} \frac{1}{2} & -4 & \frac{5}{2} \\ 1 & -6 & 3 \\ 1 & 2 & -1 \\ \end{matrix} \right]\]
C.	\[\frac{1}{2}\left[ \begin{matrix} 1 & 2 & 3 \\ 3 & 2 & 1 \\ 4 & 2 & 3 \\ \end{matrix} \right]\]
D.	\[\frac{1}{2}\left[ \begin{matrix} 1 & -1 & -1 \\ -8 & 6 & -2 \\ 5 & -3 & 1 \\ \end{matrix} \right]\]
Answer» B. \[\left[ \begin{matrix} \frac{1}{2} & -4 & \frac{5}{2} \\ 1 & -6 & 3 \\ 1 & 2 & -1 \\ \end{matrix} \right]\]

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