The integral &conint;c(ydx - xdy) is evaluated along the circle x + y – McqOptions

MCQOPTIONS

1.	The integral ∮_c(ydx - xdy) is evaluated along the circle x + y = 1/4 traversed in counter clockwise direction. The integral is equal to
A.	0
B.	- /4
C.	- /2
D.	/4
Answer» D. /4

Discussion

No Comment Found

Related MCQs

Consider the function f(x) = 2x<<sup>3</sup> 3x in the domain [ 1, 2]. The global minimum of f(x) is
The solution of the differential equation (dy / dx) + 2xy = e<sup>-x </sup> with y(0) = 1 is
The solution of the initial value problem (dy / dx) = 2xy; y(0) = 2 is
A box contains 20 defective items and 80 nondefective items. If two items are selected at random without replacement, what will be the probability that both items are defective?
A single die is thrown twice. What is the probability that the sum is neither 8 nor 9?
The argument of the complex number {(1 + i) / (1 - i)} , where i = <span style=" text-decoration: overline;">-1</span> is
The following surface integral is to be evaluated over a sphere for the given steady velocity vector field <span style="text-decoration:overline;">F</span> = x + y&jcirc; + zk defined with respect to a Cartesian coordinate system having i, j and k as unit base vectors.<br>&Int;<sub>s</sub> ( <span style="text-decoration:overline;">F</span>.n )dA<br>where S is the sphere, x<sup>2</sup> + y<sup>2</sup> + z<sup>3</sup> = 1 and n is the outward unit normal vector to the sphere. The value of the surface integral is
The divergence of the vector field 3xz + 2xy&jcirc; - yz<up>2k at a point (1, 1, 1) is equal to </up>
The directional derivative of the scalar function f(x, y, z) = x<sup>2</sup> + 2y<sup>2</sup> + z at the point P = (1, 1, 2) in the direction of the vector a = 3 - 4&jcirc; is
Divergence of the vector field <br>x<sup>2</sup>z + xy&jcirc; - yz<sup>2</sup>k at (1, -1, 1) is