MCQOPTIONS
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| 1. |
The gravitational field due to a mass distribution is \[\operatorname{E}=K/{{x}^{3}}\]in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is |
| A. | \[K/x\] |
| B. | \[K/2x\] |
| C. | \[\operatorname{K}/{{x}^{2}}\] |
| D. | \[\operatorname{K}/2{{x}^{2}}\] |
| Answer» E. | |