MCQOPTIONS
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| 1. |
The gravitational field due to a mass distribution is \[E=K/{{x}^{3}}\] in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is [MP PET 1994] |
| A. | \[K/x\] |
| B. | \[K/2x\] |
| C. | \[K/{{x}^{2}}\] |
| D. | \[K/2{{x}^{2}}\] |
| Answer» E. | |