The general solution of \[\sin x-3\sin 2x+\sin 3x=\] \[\cos x-3\cos 2x+\cos 3x\] is [IIT 1989]

\[{{(-1)}^{n}}\frac{n\pi }{2}+\frac{\pi }{8}\]

\[\frac{n\pi }{2}+\frac{\pi }{8}\]

\[2n\pi +{{\cos }^{-1}}\frac{3}{2}\]

The general solution of \[\sin x-3\sin 2x+\sin 3x=\] \[\cos x-3\cos 2x

1.	The general solution of \[\sin x-3\sin 2x+\sin 3x=\] \[\cos x-3\cos 2x+\cos 3x\] is [IIT 1989]
A.	\[n\pi +\frac{\pi }{8}\]
B.	\[\frac{n\pi }{2}+\frac{\pi }{8}\]
C.	\[{{(-1)}^{n}}\frac{n\pi }{2}+\frac{\pi }{8}\]
D.	\[2n\pi +{{\cos }^{-1}}\frac{3}{2}\]
Answer» C. \[{{(-1)}^{n}}\frac{n\pi }{2}+\frac{\pi }{8}\]

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The general solution of \[\sin x-3\sin 2x+\sin 3x=\] \[\cos x-3\cos 2x+\cos 3x\] is [IIT 1989]

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