MCQOPTIONS
Saved Bookmarks
| 1. |
The function \[f(x)={{(x-3)}^{2}}\] satisfies all the conditions of mean value theorem in [3, 4]. A point on\[y={{(x-3)}^{2}}\], where the tangent is parallel to the chord joining (3, 0) and (4, 1) is |
| A. | \[\left( \frac{7}{2},\frac{1}{2} \right)\] |
| B. | \[\left( \frac{7}{2},\frac{1}{4} \right)\] |
| C. | (1, 4) |
| D. | (4, 1) |
| Answer» C. (1, 4) | |