The function \[f(x)=\frac{\text{ln}(\pi +x)}{\text{ln}(e+x)}\] is [IIT 1995]

Decreasing on \[\left[ 0,\frac{\pi }{e} \right)\]and increasing on \[\left[ \frac{\pi }{e},\infty \right)\]

Increasing on \[\left[ 0,\,\infty \right)\]

Decreasing on \[\left[ 0,\,\infty \right)\]

Increasing on \[\left[ 0,\frac{\pi }{e} \right)\] and decreasing on \[\left[ \frac{\pi }{e},\infty \right)\]

The function \[f(x)=\frac{\text{ln}(\pi +x)}{\text{ln}(e+x)}\] is

1.	The function \[f(x)=\frac{\text{ln}(\pi +x)}{\text{ln}(e+x)}\] is [IIT 1995]
A.	Increasing on \[\left[ 0,\,\infty \right)\]
B.	Decreasing on \[\left[ 0,\,\infty \right)\]
C.	Decreasing on \[\left[ 0,\frac{\pi }{e} \right)\]and increasing on \[\left[ \frac{\pi }{e},\infty \right)\]
D.	Increasing on \[\left[ 0,\frac{\pi }{e} \right)\] and decreasing on \[\left[ \frac{\pi }{e},\infty \right)\]
Answer» C. Decreasing on \[\left[ 0,\frac{\pi }{e} \right)\]and increasing on \[\left[ \frac{\pi }{e},\infty \right)\]

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The function \[f(x)=\frac{\text{ln}(\pi +x)}{\text{ln}(e+x)}\] is [IIT 1995]

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