The function \[f(x)\] defined by\[f(x)=\left\{ \begin{matrix} {{\log }_{(4x-3)}}({{x}^{2}}-2x+5),\,\,\,\,\,\,\frac{3}{4}

is discontinuous at x=1 since \[f({{1}^{+}})\]does not exist though \[f({{1}^{-}})\]exists

is discontinuous at x=1 since \[f({{1}^{-}})\]does not exist thought \[f({{1}^{+}})\]exists

is discontinuous at x=1 since neither \[f({{1}^{+}})\]nor \[f({{1}^{-}})\]exists.

The function \[f(x)\] defined by\[f(x)=\left\{ \begin{matrix} {{\

1.	The function \[f(x)\] defined by\[f(x)=\left\{ \begin{matrix} {{\log }_{(4x-3)}}({{x}^{2}}-2x+5),\,\,\,\,\,\,\frac{3}{4}
A.	is continuous at x=1
B.	is discontinuous at x=1 since \[f({{1}^{+}})\]does not exist though \[f({{1}^{-}})\]exists
C.	is discontinuous at x=1 since \[f({{1}^{-}})\]does not exist thought \[f({{1}^{+}})\]exists
D.	is discontinuous at x=1 since neither \[f({{1}^{+}})\]nor \[f({{1}^{-}})\]exists.
Answer» E.

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The function \[f(x)\] defined by\[f(x)=\left\{ \begin{matrix} {{\log }_{(4x-3)}}({{x}^{2}}-2x+5),\,\,\,\,\,\,\frac{3}{4}

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