The function \[f(\theta )=\frac{d}{d\theta }\int\limits_{0}^{\theta }{\frac{dx}{1-\cos \theta \,\,\cos x}}\] satisfies the differential equation

\[\frac{df}{d\theta }-2f(\theta )cot\theta =0\]

\[\frac{df}{d\theta }+2f(\theta )cot\theta =0\]

\[\frac{df}{d\theta }+2f(\theta )=0\]

\[\frac{df}{d\theta }-2f(\theta )=0\]

The function \[f(\theta )=\frac{d}{d\theta }\int\limits_{0}^{\theta }{

1.	The function \[f(\theta )=\frac{d}{d\theta }\int\limits_{0}^{\theta }{\frac{dx}{1-\cos \theta \,\,\cos x}}\] satisfies the differential equation
A.	\[\frac{df}{d\theta }+2f(\theta )cot\theta =0\]
B.	\[\frac{df}{d\theta }-2f(\theta )cot\theta =0\]
C.	\[\frac{df}{d\theta }+2f(\theta )=0\]
D.	\[\frac{df}{d\theta }-2f(\theta )=0\]
Answer» B. \[\frac{df}{d\theta }-2f(\theta )cot\theta =0\]

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The function \[f(\theta )=\frac{d}{d\theta }\int\limits_{0}^{\theta }{\frac{dx}{1-\cos \theta \,\,\cos x}}\] satisfies the differential equation

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