The function defined by \[f(x)\,=\,\left\{ \begin{matrix} {{\left( {{x}^{2}}+{{e}^{\frac{1}{2-x}}} \right)}^{-1}} & , & x\ne 2 \\ k & , & x=2 \\ \end{matrix} \right.\], is continuous from right at the point x = 2, then k is equal to [Orissa JEE 2002]

The function defined by \[f(x)\,=\,\left\{ \begin{matrix} {{\left

1.	The function defined by \[f(x)\,=\,\left\{ \begin{matrix} {{\left( {{x}^{2}}+{{e}^{\frac{1}{2-x}}} \right)}^{-1}} & , & x\ne 2 \\ k & , & x=2 \\ \end{matrix} \right.\], is continuous from right at the point x = 2, then k is equal to [Orissa JEE 2002]
A.	0
B.	1/4
C.	?1/4
D.	None of these
Answer» C. ?1/4

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The function defined by \[f(x)\,=\,\left\{ \begin{matrix} {{\left( {{x}^{2}}+{{e}^{\frac{1}{2-x}}} \right)}^{-1}} & , & x\ne 2 \\ k & , & x=2 \\ \end{matrix} \right.\], is continuous from right at the point x = 2, then k is equal to [Orissa JEE 2002]

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