The formula \[{{\sin }^{-1}}\{2x(1-{{x}^{2}})\}=2si{{n}^{-1}}x\] is true for all values of x lying in the interval

\[\left[ -1/\sqrt{2},1/\sqrt{2} \right]\]

The formula \[{{\sin }^{-1}}\{2x(1-{{x}^{2}})\}=2si{{n}^{-1}}x\] is tr

1.	The formula \[{{\sin }^{-1}}\{2x(1-{{x}^{2}})\}=2si{{n}^{-1}}x\] is true for all values of x lying in the interval
A.	\[[-1,1]\]
B.	\[[0,1]\]
C.	\[[-1,0]\]
D.	\[\left[ -1/\sqrt{2},1/\sqrt{2} \right]\]
Answer» E.

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The formula \[{{\sin }^{-1}}\{2x(1-{{x}^{2}})\}=2si{{n}^{-1}}x\] is true for all values of x lying in the interval

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