The formation of the oxide ion \[O_{(g)}^{2-}\] requires first an exothermic and then an endothermic step as shown below \[{{O}_{(g)}}+{{e}^{-}}=O_{(g)}^{-}\Delta {{H}^{0}}=-142\ kJmo{{l}^{-1}}\] \[O_{(g)}^{-}+{{e}^{-}}=O_{(g)}^{2-}\Delta {{H}^{0}}=844\ kJmo{{l}^{-1}}\] This is because [AIEEE 2004]

Oxygen has high electron affinity

\[{{O}^{-}}\] ion will tend to resist the addition of another electron

\[{{O}^{-}}\]ion has comparatively larger size than oxygen atom

The formation of the oxide ion \[O_{(g)}^{2-}\] requires first an exot

1.	The formation of the oxide ion \[O_{(g)}^{2-}\] requires first an exothermic and then an endothermic step as shown below \[{{O}_{(g)}}+{{e}^{-}}=O_{(g)}^{-}\Delta {{H}^{0}}=-142\ kJmo{{l}^{-1}}\] \[O_{(g)}^{-}+{{e}^{-}}=O_{(g)}^{2-}\Delta {{H}^{0}}=844\ kJmo{{l}^{-1}}\] This is because [AIEEE 2004]
A.	\[{{O}^{-}}\] ion will tend to resist the addition of another electron
B.	Oxygen has high electron affinity
C.	Oxygen is more electronegative
D.	\[{{O}^{-}}\]ion has comparatively larger size than oxygen atom
Answer» B. Oxygen has high electron affinity

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The formation of the oxide ion \[O_{(g)}^{2-}\] requires first an exothermic and then an endothermic step as shown below \[{{O}_{(g)}}+{{e}^{-}}=O_{(g)}^{-}\Delta {{H}^{0}}=-142\ kJmo{{l}^{-1}}\] \[O_{(g)}^{-}+{{e}^{-}}=O_{(g)}^{2-}\Delta {{H}^{0}}=844\ kJmo{{l}^{-1}}\] This is because [AIEEE 2004]

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