The expression which is the general solution of the differential equation \[\frac{dy}{dx}+\frac{x}{1-{{x}^{2}}}y=x\sqrt{y}\] is

\[y{{(1-{{x}^{2}})}^{\frac{1}{4}}}=c(1-{{x}^{2}})\]

\[\sqrt{y}+\frac{1}{3}(1-{{x}^{2}})=c{{(1-{{x}^{2}})}^{\frac{1}{4}}}\]

\[\sqrt{y}{{(1-{{x}^{2}})}^{\frac{1}{4}}}=\frac{1}{3}(1-{{x}^{2}})+c\]

The expression which is the general solution of the differential equat

1.	The expression which is the general solution of the differential equation \[\frac{dy}{dx}+\frac{x}{1-{{x}^{2}}}y=x\sqrt{y}\] is
A.	\[\sqrt{y}+\frac{1}{3}(1-{{x}^{2}})=c{{(1-{{x}^{2}})}^{\frac{1}{4}}}\]
B.	\[y{{(1-{{x}^{2}})}^{\frac{1}{4}}}=c(1-{{x}^{2}})\]
C.	\[\sqrt{y}{{(1-{{x}^{2}})}^{\frac{1}{4}}}=\frac{1}{3}(1-{{x}^{2}})+c\]
D.	None of these
Answer» B. \[y{{(1-{{x}^{2}})}^{\frac{1}{4}}}=c(1-{{x}^{2}})\]

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The expression which is the general solution of the differential equation \[\frac{dy}{dx}+\frac{x}{1-{{x}^{2}}}y=x\sqrt{y}\] is

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