1.

The expression for the capacity of the capacitor formed by compound dielectric placed between the plates of a parallel plate capacitor as shown in figure, will be (area of plate \[=A\])           [MP PET 1996]

A.    \[\frac{{{\varepsilon }_{0}}A}{\left( \frac{{{d}_{1}}}{{{K}_{1}}}+\frac{{{d}_{2}}}{{{K}_{2}}}+\frac{{{d}_{3}}}{{{K}_{3}}} \right)}\]
B.     \[\frac{{{\varepsilon }_{0}}A}{\left( \frac{{{d}_{1}}+{{d}_{2}}+{{d}_{3}}}{{{K}_{1}}+{{K}_{2}}+{{K}_{3}}} \right)}\]
C.    \[\frac{{{\varepsilon }_{0}}A({{K}_{1}}{{K}_{2}}{{K}_{3}})}{{{d}_{1}}{{d}_{2}}{{d}_{3}}}\]
D.          \[{{\varepsilon }_{0}}\left( \frac{A{{K}_{1}}}{{{d}_{1}}}+\frac{A{{K}_{2}}}{{{d}_{2}}}+\frac{A{{K}_{3}}}{{{d}_{3}}} \right)\]
Answer» B.     \[\frac{{{\varepsilon }_{0}}A}{\left( \frac{{{d}_{1}}+{{d}_{2}}+{{d}_{3}}}{{{K}_{1}}+{{K}_{2}}+{{K}_{3}}} \right)}\]


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