MCQOPTIONS
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| 1. |
The expression for the capacity of the capacitor formed by compound dielectric placed between the plates of a parallel plate capacitor as shown in figure, will be (area of plate \[=A\]) [MP PET 1996] |
| A. | \[\frac{{{\varepsilon }_{0}}A}{\left( \frac{{{d}_{1}}}{{{K}_{1}}}+\frac{{{d}_{2}}}{{{K}_{2}}}+\frac{{{d}_{3}}}{{{K}_{3}}} \right)}\] |
| B. | \[\frac{{{\varepsilon }_{0}}A}{\left( \frac{{{d}_{1}}+{{d}_{2}}+{{d}_{3}}}{{{K}_{1}}+{{K}_{2}}+{{K}_{3}}} \right)}\] |
| C. | \[\frac{{{\varepsilon }_{0}}A({{K}_{1}}{{K}_{2}}{{K}_{3}})}{{{d}_{1}}{{d}_{2}}{{d}_{3}}}\] |
| D. | \[{{\varepsilon }_{0}}\left( \frac{A{{K}_{1}}}{{{d}_{1}}}+\frac{A{{K}_{2}}}{{{d}_{2}}}+\frac{A{{K}_{3}}}{{{d}_{3}}} \right)\] |
| Answer» B. \[\frac{{{\varepsilon }_{0}}A}{\left( \frac{{{d}_{1}}+{{d}_{2}}+{{d}_{3}}}{{{K}_{1}}+{{K}_{2}}+{{K}_{3}}} \right)}\] | |