MCQOPTIONS
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| 1. |
The escape velocity for a body projected vertically upwards from the surface of earth is 11 km/s. If the body is projected at an angle of 45o with the vertical, the escape velocity will be [AIEEE 2003] |
| A. | \[\frac{11}{\sqrt{2}}km/s\] |
| B. | \[11\sqrt{2}\,km/s\] |
| C. | 22 km/s |
| D. | 11 km/s |
| Answer» E. | |