1.

The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is

A. h/(kG² + h²)
B. (kG² + h²)/h
C. h²/(kG² + h²)
D. (kG² + h²)/h²
Answer» C. h¬¨‚â§/(kG¬¨‚â§ + h¬¨‚â§)


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