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1. |
The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is |
A. | h/(kG² + h²) |
B. | (kG² + h²)/h |
C. | h²/(kG² + h²) |
D. | (kG² + h²)/h² |
Answer» C. h¬¨‚â§/(kG¬¨‚â§ + h¬¨‚â§) | |