The equilibrium constant of the reaction \[{{H}_{2}}(g)+{{I}_{2}}(g)\] ⇌ \[2HI(g)\] is 64. If the volume of the container is reduced to one fourth of its original volume, the value of the equilibrium constant will be [MP PET 1996]

The equilibrium constant of the reaction \[{{H}_{2}}(g)+{{I}_{2}}(g)\]

1.	The equilibrium constant of the reaction \[{{H}_{2}}(g)+{{I}_{2}}(g)\] ⇌ \[2HI(g)\] is 64. If the volume of the container is reduced to one fourth of its original volume, the value of the equilibrium constant will be [MP PET 1996]
A.	16
B.	32
C.	64
D.	128
Answer» D. 128

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The equilibrium constant of the reaction \[{{H}_{2}}(g)+{{I}_{2}}(g)\] ⇌ \[2HI(g)\] is 64. If the volume of the container is reduced to one fourth of its original volume, the value of the equilibrium constant will be [MP PET 1996]

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