The equations of the line passing through the point (1,2,-4) and perpendicular to the two lines \[\frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7}\] and \[\frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5}\], will be [AI CBSE 1983]

\[\frac{x-1}{-2}=\frac{y-2}{3}=\frac{z+4}{8}\]

\[\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}\]

The equations of the line passing through the point (1,2,-4) and per

1.	The equations of the line passing through the point (1,2,-4) and perpendicular to the two lines \[\frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7}\] and \[\frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5}\], will be [AI CBSE 1983]
A.	\[\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}\]
B.	\[\frac{x-1}{-2}=\frac{y-2}{3}=\frac{z+4}{8}\]
C.	\[\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}\]
D.	None of these
Answer» B. \[\frac{x-1}{-2}=\frac{y-2}{3}=\frac{z+4}{8}\]

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The equations of the line passing through the point (1,2,-4) and perpendicular to the two lines \[\frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7}\] and \[\frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5}\], will be [AI CBSE 1983]

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