MCQOPTIONS
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| 1. |
The equations of motion of two stones thrown vertically upwards simultaneously are \[s=19.6\,t-4.9\,{{t}^{2}}\] and \[s=9.8\,t-4.9\,{{t}^{2}}\] respectively and the maximum height attained by the first one is h. When the height of the first stone is maximum, the height of the second stone will be |
| A. | h/3 |
| B. | 2h |
| C. | h |
| D. | 0 |
| Answer» E. | |