The equation \[{{\tan }^{-1}}(1+x)+ta{{n}^{-1}}(1-x)=\frac{\pi }{2}\] is satisfied by

The equation \[{{\tan }^{-1}}(1+x)+ta{{n}^{-1}}(1-x)=\frac{\pi }{2}\]

1.	The equation \[{{\tan }^{-1}}(1+x)+ta{{n}^{-1}}(1-x)=\frac{\pi }{2}\] is satisfied by
A.	\[x=1\]
B.	\[x=-1\]
C.	\[x=0\]
D.	\[x=\frac{1}{2}\]
Answer» D. \[x=\frac{1}{2}\]

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The equation \[{{\tan }^{-1}}(1+x)+ta{{n}^{-1}}(1-x)=\frac{\pi }{2}\] is satisfied by

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