The equation \[{{\sin }^{4}}x+{{\cos }^{4}}x+\sin 2x+\alpha =0\]is solvable for

\[-\frac{1}{2}\le \alpha \le \frac{1}{2}\]

\[-\frac{3}{2}\le \alpha \le \frac{1}{2}\]

The equation \[{{\sin }^{4}}x+{{\cos }^{4}}x+\sin 2x+\alpha =0\]is sol

1.	The equation \[{{\sin }^{4}}x+{{\cos }^{4}}x+\sin 2x+\alpha =0\]is solvable for
A.	\[-\frac{1}{2}\le \alpha \le \frac{1}{2}\]
B.	\[-3\le \alpha \le 1\]
C.	\[-\frac{3}{2}\le \alpha \le \frac{1}{2}\]
D.	\[-1\le \alpha \le 1\]
Answer» D. \[-1\le \alpha \le 1\]

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The equation \[{{\sin }^{4}}x+{{\cos }^{4}}x+\sin 2x+\alpha =0\]is solvable for

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