MCQOPTIONS
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| 1. |
The equation of the tangent to the parabola \[{{y}^{2}}=4ax\] at point \[(a/{{t}^{2}},\ 2a/t)\] is [RPET 1996] |
| A. | \[ty=x{{t}^{2}}+a\] |
| B. | \[ty=x+a{{t}^{2}}\] |
| C. | \[y=tx+a{{t}^{2}}\] |
| D. | \[y=tx+(a/{{t}^{2}})\] |
| Answer» B. \[ty=x+a{{t}^{2}}\] | |