The equation of the tangent at the point \[(a\sec \theta ,\ b\tan \theta )\] of the conic \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\], is

\[\frac{x+a\sec \theta }{{{a}^{2}}}-\frac{y+b\tan \theta }{{{b}^{2}}}=1\]

\[x{{\sec }^{2}}\theta -y{{\tan }^{2}}\theta =1\]

\[\frac{x}{a}\sec \theta -\frac{y}{b}\tan \theta =1\]

The equation of the tangent at the point \[(a\sec \theta ,\ b\tan \the

1.	The equation of the tangent at the point \[(a\sec \theta ,\ b\tan \theta )\] of the conic \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\], is
A.	\[x{{\sec }^{2}}\theta -y{{\tan }^{2}}\theta =1\]
B.	\[\frac{x}{a}\sec \theta -\frac{y}{b}\tan \theta =1\]
C.	\[\frac{x+a\sec \theta }{{{a}^{2}}}-\frac{y+b\tan \theta }{{{b}^{2}}}=1\]
D.	None of these
Answer» C. \[\frac{x+a\sec \theta }{{{a}^{2}}}-\frac{y+b\tan \theta }{{{b}^{2}}}=1\]

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The equation of the tangent at the point \[(a\sec \theta ,\ b\tan \theta )\] of the conic \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\], is

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