The equation of the plane through the point \[(2,-1,-3)\]and parallel to the lines \[\frac{x-1}{3}=\frac{y+2}{2}=\frac{z}{-4}\] and \[\frac{x}{2}=\frac{y-1}{-3}=\frac{z-2}{2}\] is [Kerala (Engg.) 2005]

The equation of the plane through the point \[(2,-1,-3)\]and parallel

1.	The equation of the plane through the point \[(2,-1,-3)\]and parallel to the lines \[\frac{x-1}{3}=\frac{y+2}{2}=\frac{z}{-4}\] and \[\frac{x}{2}=\frac{y-1}{-3}=\frac{z-2}{2}\] is [Kerala (Engg.) 2005]
A.	\[8x+14y+13z+37=0\]
B.	\[8x-14y+13z+37=0\]
C.	\[8x+14y-13z+37=0\]
D.	\[8x+14y+13z-37=0\]
E.	(e) \[8x-14y-13z-37=0\]
Answer» B. \[8x-14y+13z+37=0\]

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The equation of the plane through the point \[(2,-1,-3)\]and parallel to the lines \[\frac{x-1}{3}=\frac{y+2}{2}=\frac{z}{-4}\] and \[\frac{x}{2}=\frac{y-1}{-3}=\frac{z-2}{2}\] is [Kerala (Engg.) 2005]

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