The equation of the perpendicular from the point \[(\alpha ,\beta ,\gamma )\] to the plane \[ax+by+cz+d=0\]is [MP PET 2003]

\[a(x-\alpha )+b(y-\beta )+c(z-\gamma )=abc\]

\[a(x-\alpha )+b(y-\beta )+c(z-\gamma )=0\]

\[\frac{x-\alpha }{a}=\frac{y-\beta }{b}=\frac{z-\gamma }{c}\]

The equation of the perpendicular from the point \[(\alpha ,\beta

1.	The equation of the perpendicular from the point \[(\alpha ,\beta ,\gamma )\] to the plane \[ax+by+cz+d=0\]is [MP PET 2003]
A.	\[a(x-\alpha )+b(y-\beta )+c(z-\gamma )=0\]
B.	\[\frac{x-\alpha }{a}=\frac{y-\beta }{b}=\frac{z-\gamma }{c}\]
C.	\[a(x-\alpha )+b(y-\beta )+c(z-\gamma )=abc\]
D.	None of these
Answer» C. \[a(x-\alpha )+b(y-\beta )+c(z-\gamma )=abc\]

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The equation of the perpendicular from the point \[(\alpha ,\beta ,\gamma )\] to the plane \[ax+by+cz+d=0\]is [MP PET 2003]

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