The equation of the normal to the hyperbola \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1\] at \[(-4,\ 0)\] is [UPSEAT 2002]

The equation of the normal to the hyperbola \[\frac{{{x}^{2}}}{16}-\fr

1.	The equation of the normal to the hyperbola \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1\] at \[(-4,\ 0)\] is [UPSEAT 2002]
A.	\[y=0\]
B.	\[y=x\]
C.	\[x=0\]
D.	\[x=-y\]
Answer» B. \[y=x\]

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The equation of the normal to the hyperbola \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1\] at \[(-4,\ 0)\] is [UPSEAT 2002]

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