The equation of the locus of foot of perpendiculars drawn from the origin to the line passing through a fixed point (a, b), is

\[{{x}^{2}}+{{y}^{2}}+ax+by=0\]

\[{{x}^{2}}+{{y}^{2}}-ax-by=0\]

\[{{x}^{2}}+{{y}^{2}}-2ax-2by=0\]

The equation of the locus of foot of perpendiculars drawn from the ori

1.	The equation of the locus of foot of perpendiculars drawn from the origin to the line passing through a fixed point (a, b), is
A.	\[{{x}^{2}}+{{y}^{2}}-ax-by=0\]
B.	\[{{x}^{2}}+{{y}^{2}}+ax+by=0\]
C.	\[{{x}^{2}}+{{y}^{2}}-2ax-2by=0\]
D.	None of these
Answer» B. \[{{x}^{2}}+{{y}^{2}}+ax+by=0\]

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The equation of the locus of foot of perpendiculars drawn from the origin to the line passing through a fixed point (a, b), is

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