MCQOPTIONS
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| 1. |
The equation of the hyperbola whose foci are (6, 4) and (?4, 4) and eccentricity 2 is given by [MP PET 1993] |
| A. | \[12{{x}^{2}}-4{{y}^{2}}-24x+32y-127=0\] |
| B. | \[12{{x}^{2}}+4{{y}^{2}}+24x-32y-127=0\] |
| C. | \[12{{x}^{2}}-4{{y}^{2}}-24x-32y+127=0\] |
| D. | \[12{{x}^{2}}-4{{y}^{2}}+24x+32y+127=0\] |
| Answer» B. \[12{{x}^{2}}+4{{y}^{2}}+24x-32y-127=0\] | |