1.

The equation of the hyperbola whose foci are (6, 4) and    (?4, 4) and eccentricity 2 is given by       [MP PET 1993]

A.            \[12{{x}^{2}}-4{{y}^{2}}-24x+32y-127=0\]
B.            \[12{{x}^{2}}+4{{y}^{2}}+24x-32y-127=0\]
C.            \[12{{x}^{2}}-4{{y}^{2}}-24x-32y+127=0\]
D.            \[12{{x}^{2}}-4{{y}^{2}}+24x+32y+127=0\]
Answer» B.            \[12{{x}^{2}}+4{{y}^{2}}+24x-32y-127=0\]


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