The equation of the circle of radius 5 and touching the coordinate axes in third quadrant is [EAMCET 2002]

\[{{(x-5)}^{2}}+{{(y+5)}^{2}}=25\]

\[{{(x+4)}^{2}}+{{(y+4)}^{2}}=25\]

\[{{(x+6)}^{2}}+{{(y+6)}^{2}}=25\]

\[{{(x+5)}^{2}}+{{(y+5)}^{2}}=25\]

The equation of the circle of radius 5 and touching the coordinate

1.	The equation of the circle of radius 5 and touching the coordinate axes in third quadrant is [EAMCET 2002]
A.	\[{{(x-5)}^{2}}+{{(y+5)}^{2}}=25\]
B.	\[{{(x+4)}^{2}}+{{(y+4)}^{2}}=25\]
C.	\[{{(x+6)}^{2}}+{{(y+6)}^{2}}=25\]
D.	\[{{(x+5)}^{2}}+{{(y+5)}^{2}}=25\]
Answer» E.

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The equation of the circle of radius 5 and touching the coordinate axes in third quadrant is [EAMCET 2002]

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