MCQOPTIONS
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| 1. |
The equation of stationary wave along a stretched string is given by \[y=5\sin \frac{\pi x}{3}\cos 40\pi t\], where x and y are in cm and t in second. The separation between two adjacent nodes is [CPMT 1990; MP PET 1999; AMU 1999; DPMT 2004; BHU 2005] |
| A. | 1.5 cm |
| B. | 3 cm |
| C. | 6 cm |
| D. | 4 cm |
| Answer» C. 6 cm | |