MCQOPTIONS
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| 1. |
The equation of a projectile is \[y=\sqrt{3}x-\frac{\text{g}{{\text{x}}^{2}}}{20}\] The angle of projection is given by |
| A. | \[\text{tan}\theta \,\text{=}\frac{1}{\sqrt{3}}\] |
| B. | \[\text{tan}\theta \,\text{=}\,\sqrt{3}\] |
| C. | \[\frac{\pi }{2}\] |
| D. | zero. |
| Answer» C. \[\frac{\pi }{2}\] | |