MCQOPTIONS
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| 1. |
The equation of a circle that intersects the circle \[{{x}^{2}}+{{y}^{2}}+14x+6y+2=0\]orthogonally and whose centre is (0, 2) is [MP PET 1998] |
| A. | \[{{x}^{2}}+{{y}^{2}}-4y-6=0\] |
| B. | \[{{x}^{2}}+{{y}^{2}}+4y-14=0\] |
| C. | \[{{x}^{2}}+{{y}^{2}}+4y+14=0\] |
| D. | \[{{x}^{2}}+{{y}^{2}}-4y-14=0\] |
| Answer» E. | |