1.

The equation of a circle that intersects the circle \[{{x}^{2}}+{{y}^{2}}+14x+6y+2=0\]orthogonally and whose centre is (0, 2) is [MP PET 1998]

A. \[{{x}^{2}}+{{y}^{2}}-4y-6=0\]
B. \[{{x}^{2}}+{{y}^{2}}+4y-14=0\]
C. \[{{x}^{2}}+{{y}^{2}}+4y+14=0\]
D. \[{{x}^{2}}+{{y}^{2}}-4y-14=0\]
Answer» E.


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