The enthalpy of neutralisation of $$N{{H}_{4}}OH$$and $$C{{H}_{3}}COOH$$ is $$-10.5\text{ }kcal\text{ }mo{{l}^{-1}}$$ and enthalpy of neutralisation of $$C{{H}_{3}}COOH$$ with strong base is$$-12.5\,kcal\text{ }mo{{l}^{-1}}$$. The enthalpy of ionisation of $$N{{H}_{4}}OH$$ will be

Question

TuteeHUB · Accepted Answer

$$3.0\text{ }kcal\text{ }mo{{l}^{-1}}$$

TuteeHUB · Answer

$$3.2\text{ }kcal\text{ }mo{{l}^{-1}}$$

TuteeHUB · Answer

$$2.0\text{ }kcal\text{ }mo{{l}^{-1}}$$

TuteeHUB · Answer

$$4.0\text{ }kcal\text{ }mo{{l}^{-1}}$$

1.	The enthalpy of neutralisation of \[N{{H}_{4}}OH\]and \[C{{H}_{3}}COOH\] is \[-10.5\text{ }kcal\text{ }mo{{l}^{-1}}\] and enthalpy of neutralisation of \[C{{H}_{3}}COOH\] with strong base is\[-12.5\,kcal\text{ }mo{{l}^{-1}}\]. The enthalpy of ionisation of \[N{{H}_{4}}OH\] will be
A.	\[3.2\text{ }kcal\text{ }mo{{l}^{-1}}\]
B.	\[2.0\text{ }kcal\text{ }mo{{l}^{-1}}\]
C.	\[3.0\text{ }kcal\text{ }mo{{l}^{-1}}\]
D.	\[4.0\text{ }kcal\text{ }mo{{l}^{-1}}\]
Answer» C. \[3.0\text{ }kcal\text{ }mo{{l}^{-1}}\]

The enthalpy of neutralisation of \[N{{H}_{4}}OH\]and \[C{{H}_{3}}COOH\] is \[-10.5\text{ }kcal\text{ }mo{{l}^{-1}}\] and enthalpy of neutralisation of \[C{{H}_{3}}COOH\] with strong base is\[-12.5\,kcal\text{ }mo{{l}^{-1}}\]. The enthalpy of ionisation of \[N{{H}_{4}}OH\] will be

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