The energy of \[H{{e}^{+}}\] in the ground state is -54.4 eV, then the – McqOptions

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1.	The energy of \[H{{e}^{+}}\] in the ground state is -54.4 eV, then the energy of \[L{{i}^{++}}\] in the first excited state will be
A.	-30.6 eV
B.	27.2 eV
C.	-13.6 eV
D.	- 27.2 eV
Answer» B. 27.2 eV

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