The energy of an electron revolving in \[{{n}^{th}}\] Bohr's orbit of an atom is given by the expression [MP PMT 1999]

\[{{E}_{n}}=-\frac{2\pi {{m}^{2}}{{e}^{2}}{{z}^{4}}}{{{n}^{2}}{{h}^{2}}}\]

\[{{E}_{n}}=-\frac{2{{\pi }^{2}}{{m}^{4}}{{e}^{2}}{{z}^{2}}}{{{n}^{2}}{{h}^{2}}}\]

\[{{E}_{n}}=-\frac{2{{\pi }^{2}}m{{e}^{2}}{{z}^{2}}}{{{n}^{2}}{{h}^{2}}}\]

\[{{E}_{n}}=-\frac{2{{\pi }^{2}}m{{e}^{4}}{{z}^{2}}}{{{n}^{2}}{{h}^{2}}}\]

The energy of an electron revolving in \[{{n}^{th}}\] Bohr's orbit of

1.	The energy of an electron revolving in \[{{n}^{th}}\] Bohr's orbit of an atom is given by the expression [MP PMT 1999]
A.	\[{{E}_{n}}=-\frac{2{{\pi }^{2}}{{m}^{4}}{{e}^{2}}{{z}^{2}}}{{{n}^{2}}{{h}^{2}}}\]
B.	\[{{E}_{n}}=-\frac{2{{\pi }^{2}}m{{e}^{2}}{{z}^{2}}}{{{n}^{2}}{{h}^{2}}}\]
C.	\[{{E}_{n}}=-\frac{2{{\pi }^{2}}m{{e}^{4}}{{z}^{2}}}{{{n}^{2}}{{h}^{2}}}\]
D.	\[{{E}_{n}}=-\frac{2\pi {{m}^{2}}{{e}^{2}}{{z}^{4}}}{{{n}^{2}}{{h}^{2}}}\]
Answer» D. \[{{E}_{n}}=-\frac{2\pi {{m}^{2}}{{e}^{2}}{{z}^{4}}}{{{n}^{2}}{{h}^{2}}}\]

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The energy of an electron revolving in \[{{n}^{th}}\] Bohr's orbit of an atom is given by the expression [MP PMT 1999]

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