MCQOPTIONS
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MCQOPTIONS
| 1. |
The energy loss due to friction (Ef) in a circular conduit (on the basis of per unit mass) is given by_____ |
| A. | Ef = 4fLv̅²/2D |
| B. | Ef = 8fLv̅²/2D |
| C. | Ef = 4fLv̅³/2D |
| D. | Ef = 4fLv̅²/D |
| Answer» B. Ef = 8fLv‚àö√â‚àö√±¬¨¬®‚Äö√¢¬ß/2D | |