MCQOPTIONS
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| 1. |
The energy density of electromagnetic wave in vacuum is given by the relation |
| A. | \[\frac{{{E}^{2}}}{2{{\varepsilon }_{0}}}+\frac{{{B}^{2}}}{2{{\mu }_{0}}}\] |
| B. | \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}+\frac{1}{2}{{\mu }_{0}}{{B}^{2}}\] |
| C. | \[\frac{{{E}^{2}}+{{B}^{2}}}{c}\] |
| D. | \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}+\frac{{{B}^{2}}}{2{{\mu }_{0}}}\] |
| Answer» E. | |