1.

The energy density of electromagnetic wave in vacuum is given by the relation

A. \[\frac{{{E}^{2}}}{2{{\varepsilon }_{0}}}+\frac{{{B}^{2}}}{2{{\mu }_{0}}}\]  
B. \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}+\frac{1}{2}{{\mu }_{0}}{{B}^{2}}\]
C. \[\frac{{{E}^{2}}+{{B}^{2}}}{c}\]
D. \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}+\frac{{{B}^{2}}}{2{{\mu }_{0}}}\]
Answer» E.


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