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The emf of a Daniel cell at 298K is \[{{E}_{1}}\]  \[Zn|\underset{(0.01\,\,M)}{\mathop{ZnS{{O}_{4}}}}\,||\underset{(1.0\,\,M)}{\mathop{CuS{{O}_{4}}}}\,|Cu\] when the concentration of \[ZnS{{O}_{4}}\] is 1.0 M and that of \[CuS{{O}_{4}}\] is 0.01 M, the emf changed to \[{{E}_{2}}\]. What is the relationship between \[{{E}_{1}}\] and \[{{E}_{2}}\]     [CBSE PMT 2003]

A.                 \[{{E}_{2}}=0\ne {{E}_{1}}\]        
B.                 \[{{E}_{1}}>{{E}_{2}}\]
C.                 \[{{E}_{1}}<{{E}_{2}}\]  
D.                 \[{{E}_{1}}={{E}_{2}}\]
Answer» C.                 \[{{E}_{1}}<{{E}_{2}}\]  


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