1.

The electronic configuration of the element of atomic number 27 is

A.                 \[1{{s}^{2}},\ 2{{s}^{2}}2{{p}^{6}},\ 3{{s}^{2}}3{{p}^{6}},\ 4s\ (\uparrow \downarrow )\ 4p\ (\uparrow \downarrow )(\uparrow \downarrow )(\uparrow \downarrow )\ 5s\ (\uparrow )\]
B.                 \[1{{s}^{2}},\ 2{{s}^{2}}2{{p}^{6}},\ 3{{s}^{2}}3{{p}^{6}}3d\ (\uparrow \downarrow )(\uparrow \downarrow )(\uparrow \downarrow ),\ 4s\ (\uparrow \downarrow )\ 4p\ (\uparrow )\]
C.                 \[1{{s}^{2}},\ 2{{s}^{2}}2{{p}^{6}},\ 3{{s}^{2}}3{{p}^{6}},\ 3d\ (\uparrow \downarrow )(\uparrow \downarrow )(\uparrow \downarrow )(\uparrow \downarrow ),\ 4s\ (\uparrow )\]
D.                 \[1{{s}^{2}},\ 2{{s}^{2}}2{{p}^{6}},\ 3{{s}^{2}}3{{p}^{6}},\ 3d\ (\uparrow \downarrow )(\uparrow \downarrow )(\uparrow )(\uparrow )(\uparrow )\ 4s\ (\uparrow \downarrow )\]
Answer» E.


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