MCQOPTIONS
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| 1. |
The electronic configuration of the element of atomic number 27 is |
| A. | \[1{{s}^{2}},\ 2{{s}^{2}}2{{p}^{6}},\ 3{{s}^{2}}3{{p}^{6}},\ 4s\ (\uparrow \downarrow )\ 4p\ (\uparrow \downarrow )(\uparrow \downarrow )(\uparrow \downarrow )\ 5s\ (\uparrow )\] |
| B. | \[1{{s}^{2}},\ 2{{s}^{2}}2{{p}^{6}},\ 3{{s}^{2}}3{{p}^{6}}3d\ (\uparrow \downarrow )(\uparrow \downarrow )(\uparrow \downarrow ),\ 4s\ (\uparrow \downarrow )\ 4p\ (\uparrow )\] |
| C. | \[1{{s}^{2}},\ 2{{s}^{2}}2{{p}^{6}},\ 3{{s}^{2}}3{{p}^{6}},\ 3d\ (\uparrow \downarrow )(\uparrow \downarrow )(\uparrow \downarrow )(\uparrow \downarrow ),\ 4s\ (\uparrow )\] |
| D. | \[1{{s}^{2}},\ 2{{s}^{2}}2{{p}^{6}},\ 3{{s}^{2}}3{{p}^{6}},\ 3d\ (\uparrow \downarrow )(\uparrow \downarrow )(\uparrow )(\uparrow )(\uparrow )\ 4s\ (\uparrow \downarrow )\] |
| Answer» E. | |