1.

The electric field due to a charge at a distance of 3 m from it is 500 N/coulomb. The magnitude of the charge is \[\left[ \frac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}}\frac{N-{{m}^{2}}}{coulom{{b}^{2}}} \right]\]                                               [MP PMT 2000]

A.            2.5 micro-coulomb            
B.            2.0 micro-coulomb
C.            1.0 micro-coulomb            
D.            0.5 micro-coulomb
Answer» E.


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